8+2(c/4)=-3(c-7)

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Solution for 8+2(c/4)=-3(c-7) equation: 



8+2(c/4)=-3(c-7)

We move all terms to the left:

8+2(c/4)-(-3(c-7))=0

We add all the numbers together, and all the variables

2(+c/4)-(-3(c-7))+8=0

We multiply parentheses

2c-(-3(c-7))+8=0



We calculate terms in parentheses: -(-3(c-7)), so:

-3(c-7)

We multiply parentheses

-3c+21

Back to the equation:

-(-3c+21)



We get rid of parentheses

2c+3c-21+8=0

We add all the numbers together, and all the variables

5c-13=0

We move all terms containing c to the left, all other terms to the right

5c=13

c=13/5

c=2+3/5

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