8+2(x+3)=4(x+3)

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Solution for 8+2(x+3)=4(x+3) equation: 



8+2(x+3)=4(x+3)

We move all terms to the left:

8+2(x+3)-(4(x+3))=0

We multiply parentheses

2x-(4(x+3))+6+8=0



We calculate terms in parentheses: -(4(x+3)), so:

4(x+3)

We multiply parentheses

4x+12

Back to the equation:

-(4x+12)



We add all the numbers together, and all the variables

2x-(4x+12)+14=0

We get rid of parentheses

2x-4x-12+14=0

We add all the numbers together, and all the variables

-2x+2=0

We move all terms containing x to the left, all other terms to the right

-2x=-2

x=-2/-2

x=1

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