8+2(x+4)-4=2(x+4)+x

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Solution for 8+2(x+4)-4=2(x+4)+x equation: 



8+2(x+4)-4=2(x+4)+x

We move all terms to the left:

8+2(x+4)-4-(2(x+4)+x)=0

We add all the numbers together, and all the variables

2(x+4)-(2(x+4)+x)+4=0

We multiply parentheses

2x-(2(x+4)+x)+8+4=0



We calculate terms in parentheses: -(2(x+4)+x), so:

2(x+4)+x

We add all the numbers together, and all the variables

x+2(x+4)

We multiply parentheses

x+2x+8

We add all the numbers together, and all the variables

3x+8

Back to the equation:

-(3x+8)



We add all the numbers together, and all the variables

2x-(3x+8)+12=0

We get rid of parentheses

2x-3x-8+12=0

We add all the numbers together, and all the variables

-1x+4=0

We move all terms containing x to the left, all other terms to the right

-x=-4

x=-4/-1

x=+4

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