8+2(x-3)=8x+41

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Solution for 8+2(x-3)=8x+41 equation: 



8+2(x-3)=8x+41

We move all terms to the left:

8+2(x-3)-(8x+41)=0

We multiply parentheses

2x-(8x+41)-6+8=0

We get rid of parentheses

2x-8x-41-6+8=0

We add all the numbers together, and all the variables

-6x-39=0

We move all terms containing x to the left, all other terms to the right

-6x=39

x=39/-6

x=-6+1/2

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