8+2(x-4)=12+4-3(x-5)

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Solution for 8+2(x-4)=12+4-3(x-5) equation: 



8+2(x-4)=12+4-3(x-5)

We move all terms to the left:

8+2(x-4)-(12+4-3(x-5))=0

We multiply parentheses

2x-(12+4-3(x-5))-8+8=0



We calculate terms in parentheses: -(12+4-3(x-5)), so:

12+4-3(x-5)

determiningTheFunctionDomain
-3(x-5)+12+4

We add all the numbers together, and all the variables

-3(x-5)+16

We multiply parentheses

-3x+15+16

We add all the numbers together, and all the variables

-3x+31

Back to the equation:

-(-3x+31)



We add all the numbers together, and all the variables

2x-(-3x+31)=0

We get rid of parentheses

2x+3x-31=0

We add all the numbers together, and all the variables

5x-31=0

We move all terms containing x to the left, all other terms to the right

5x=31

x=31/5

x=6+1/5

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