8+2(x-4)=3x+4(2-x)

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Solution for 8+2(x-4)=3x+4(2-x) equation: 



8+2(x-4)=3x+4(2-x)

We move all terms to the left:

8+2(x-4)-(3x+4(2-x))=0

We add all the numbers together, and all the variables

2(x-4)-(3x+4(-1x+2))+8=0

We multiply parentheses

2x-(3x+4(-1x+2))-8+8=0



We calculate terms in parentheses: -(3x+4(-1x+2)), so:

3x+4(-1x+2)

We multiply parentheses

3x-4x+8

We add all the numbers together, and all the variables

-1x+8

Back to the equation:

-(-1x+8)



We add all the numbers together, and all the variables

2x-(-1x+8)=0

We get rid of parentheses

2x+1x-8=0

We add all the numbers together, and all the variables

3x-8=0

We move all terms containing x to the left, all other terms to the right

3x=8

x=8/3

x=2+2/3

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