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8+2(x-6)=(-2+2x)-2
We move all terms to the left:
8+2(x-6)-((-2+2x)-2)=0
We add all the numbers together, and all the variables
2(x-6)-((2x-2)-2)+8=0
We multiply parentheses
2x-((2x-2)-2)-12+8=0
We calculate terms in parentheses: -((2x-2)-2), so:We add all the numbers together, and all the variables
(2x-2)-2
We get rid of parentheses
2x-2-2
We add all the numbers together, and all the variables
2x-4
Back to the equation:
-(2x-4)
2x-(2x-4)-4=0
We get rid of parentheses
2x-2x+4-4=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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