8+2/3(6m-12)=3/5(20m-45)

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Solution for 8+2/3(6m-12)=3/5(20m-45) equation:



8+2/3(6m-12)=3/5(20m-45)
We move all terms to the left:
8+2/3(6m-12)-(3/5(20m-45))=0
Domain of the equation: 3(6m-12)!=0
m∈R
Domain of the equation: 5(20m-45))!=0
m∈R
We calculate fractions
(10m2/(3(6m-12)*5(20m-45)))+(-9m6/(3(6m-12)*5(20m-45)))+8=0
We calculate terms in parentheses: +(10m2/(3(6m-12)*5(20m-45))), so:
10m2/(3(6m-12)*5(20m-45))
We multiply all the terms by the denominator
10m2
We add all the numbers together, and all the variables
10m^2
Back to the equation:
+(10m^2)
We calculate terms in parentheses: +(-9m6/(3(6m-12)*5(20m-45))), so:
-9m6/(3(6m-12)*5(20m-45))
We multiply all the terms by the denominator
-9m6
We add all the numbers together, and all the variables
-9m^6
We do not support empression: m^6

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