8+2b=6(b+2)

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Solution for 8+2b=6(b+2) equation: 



8+2b=6(b+2)

We move all terms to the left:

8+2b-(6(b+2))=0



We calculate terms in parentheses: -(6(b+2)), so:

6(b+2)

We multiply parentheses

6b+12

Back to the equation:

-(6b+12)



We get rid of parentheses

2b-6b-12+8=0

We add all the numbers together, and all the variables

-4b-4=0

We move all terms containing b to the left, all other terms to the right

-4b=4

b=4/-4

b=-1

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