8+2p-4=6+2(p-1)

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Solution for 8+2p-4=6+2(p-1) equation: 



8+2p-4=6+2(p-1)

We move all terms to the left:

8+2p-4-(6+2(p-1))=0

We add all the numbers together, and all the variables

2p-(6+2(p-1))+4=0



We calculate terms in parentheses: -(6+2(p-1)), so:

6+2(p-1)

determiningTheFunctionDomain
2(p-1)+6

We multiply parentheses

2p-2+6

We add all the numbers together, and all the variables

2p+4

Back to the equation:

-(2p+4)



We get rid of parentheses

2p-2p-4+4=0

We add all the numbers together, and all the variables

=0

p=0/1

p=0

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