8+2z=6(z-2)

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Solution for 8+2z=6(z-2) equation: 



8+2z=6(z-2)

We move all terms to the left:

8+2z-(6(z-2))=0



We calculate terms in parentheses: -(6(z-2)), so:

6(z-2)

We multiply parentheses

6z-12

Back to the equation:

-(6z-12)



We get rid of parentheses

2z-6z+12+8=0

We add all the numbers together, and all the variables

-4z+20=0

We move all terms containing z to the left, all other terms to the right

-4z=-20

z=-20/-4

z=+5

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