8+3(1+2(2x-3))=6(x+8)

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Solution for 8+3(1+2(2x-3))=6(x+8) equation: 



8+3(1+2(2x-3))=6(x+8)

We move all terms to the left:

8+3(1+2(2x-3))-(6(x+8))=0



We calculate terms in parentheses: -(6(x+8)), so:

6(x+8)

We multiply parentheses

6x+48

Back to the equation:

-(6x+48)



We get rid of parentheses

3(1+2(2x-3))-6x-48+8=0

We add all the numbers together, and all the variables

-6x+3(1+2(2x-3))-40=0

We move all terms containing x to the left, all other terms to the right

-6x+3(1+2(2x-3))=40

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