8+3(1-x)=6x-4

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Solution for 8+3(1-x)=6x-4 equation:



8+3(1-x)=6x-4
We move all terms to the left:
8+3(1-x)-(6x-4)=0
We add all the numbers together, and all the variables
3(-1x+1)-(6x-4)+8=0
We multiply parentheses
-3x-(6x-4)+3+8=0
We get rid of parentheses
-3x-6x+4+3+8=0
We add all the numbers together, and all the variables
-9x+15=0
We move all terms containing x to the left, all other terms to the right
-9x=-15
x=-15/-9
x=1+2/3

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