8+3(2x+1)=5(x+1)

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Solution for 8+3(2x+1)=5(x+1) equation: 



8+3(2x+1)=5(x+1)

We move all terms to the left:

8+3(2x+1)-(5(x+1))=0

We multiply parentheses

6x-(5(x+1))+3+8=0



We calculate terms in parentheses: -(5(x+1)), so:

5(x+1)

We multiply parentheses

5x+5

Back to the equation:

-(5x+5)



We add all the numbers together, and all the variables

6x-(5x+5)+11=0

We get rid of parentheses

6x-5x-5+11=0

We add all the numbers together, and all the variables

x+6=0

We move all terms containing x to the left, all other terms to the right

x=-6

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