8+3(2x+4)=10+5(x+8)

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Solution for 8+3(2x+4)=10+5(x+8) equation: 



8+3(2x+4)=10+5(x+8)

We move all terms to the left:

8+3(2x+4)-(10+5(x+8))=0

We multiply parentheses

6x-(10+5(x+8))+12+8=0



We calculate terms in parentheses: -(10+5(x+8)), so:

10+5(x+8)

determiningTheFunctionDomain
5(x+8)+10

We multiply parentheses

5x+40+10

We add all the numbers together, and all the variables

5x+50

Back to the equation:

-(5x+50)



We add all the numbers together, and all the variables

6x-(5x+50)+20=0

We get rid of parentheses

6x-5x-50+20=0

We add all the numbers together, and all the variables

x-30=0

We move all terms containing x to the left, all other terms to the right

x=30

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