8+3(2y-4)=2(3y-2)

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Solution for 8+3(2y-4)=2(3y-2) equation:


Simplifying
8 + 3(2y + -4) = 2(3y + -2)

Reorder the terms:
8 + 3(-4 + 2y) = 2(3y + -2)
8 + (-4 * 3 + 2y * 3) = 2(3y + -2)
8 + (-12 + 6y) = 2(3y + -2)

Combine like terms: 8 + -12 = -4
-4 + 6y = 2(3y + -2)

Reorder the terms:
-4 + 6y = 2(-2 + 3y)
-4 + 6y = (-2 * 2 + 3y * 2)
-4 + 6y = (-4 + 6y)

Add '4' to each side of the equation.
-4 + 4 + 6y = -4 + 4 + 6y

Combine like terms: -4 + 4 = 0
0 + 6y = -4 + 4 + 6y
6y = -4 + 4 + 6y

Combine like terms: -4 + 4 = 0
6y = 0 + 6y
6y = 6y

Add '-6y' to each side of the equation.
6y + -6y = 6y + -6y

Combine like terms: 6y + -6y = 0
0 = 6y + -6y

Combine like terms: 6y + -6y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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