8+3(y-6)=3(y+2)-3

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Solution for 8+3(y-6)=3(y+2)-3 equation:


Simplifying
8 + 3(y + -6) = 3(y + 2) + -3

Reorder the terms:
8 + 3(-6 + y) = 3(y + 2) + -3
8 + (-6 * 3 + y * 3) = 3(y + 2) + -3
8 + (-18 + 3y) = 3(y + 2) + -3

Combine like terms: 8 + -18 = -10
-10 + 3y = 3(y + 2) + -3

Reorder the terms:
-10 + 3y = 3(2 + y) + -3
-10 + 3y = (2 * 3 + y * 3) + -3
-10 + 3y = (6 + 3y) + -3

Reorder the terms:
-10 + 3y = 6 + -3 + 3y

Combine like terms: 6 + -3 = 3
-10 + 3y = 3 + 3y

Add '-3y' to each side of the equation.
-10 + 3y + -3y = 3 + 3y + -3y

Combine like terms: 3y + -3y = 0
-10 + 0 = 3 + 3y + -3y
-10 = 3 + 3y + -3y

Combine like terms: 3y + -3y = 0
-10 = 3 + 0
-10 = 3

Solving
-10 = 3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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