8+3x2=13+x

Solution for 8+3x2=13+x equation:

8+3x^2=13+x

We move all terms to the left:

8+3x^2-(13+x)=0

We add all the numbers together, and all the variables

3x^2-(x+13)+8=0

We get rid of parentheses

3x^2-x-13+8=0

We add all the numbers together, and all the variables

3x^2-1x-5=0

a = 3; b = -1; c = -5;
Δ = b2-4ac
Δ = -12-4·3·(-5)
Δ = 61
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{61}}{2*3}=\frac{1-\sqrt{61}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{61}}{2*3}=\frac{1+\sqrt{61}}{6}
$