8+4(2u-5)=-2(5u-1)+8u

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Solution for 8+4(2u-5)=-2(5u-1)+8u equation: 



8+4(2u-5)=-2(5u-1)+8u

We move all terms to the left:

8+4(2u-5)-(-2(5u-1)+8u)=0

We multiply parentheses

8u-(-2(5u-1)+8u)-20+8=0



We calculate terms in parentheses: -(-2(5u-1)+8u), so:

-2(5u-1)+8u

We add all the numbers together, and all the variables

8u-2(5u-1)

We multiply parentheses

8u-10u+2

We add all the numbers together, and all the variables

-2u+2

Back to the equation:

-(-2u+2)



We add all the numbers together, and all the variables

8u-(-2u+2)-12=0

We get rid of parentheses

8u+2u-2-12=0

We add all the numbers together, and all the variables

10u-14=0

We move all terms containing u to the left, all other terms to the right

10u=14

u=14/10

u=1+2/5

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