8+4(2x-5)=-4(3x-2)+1

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Solution for 8+4(2x-5)=-4(3x-2)+1 equation: 



8+4(2x-5)=-4(3x-2)+1

We move all terms to the left:

8+4(2x-5)-(-4(3x-2)+1)=0

We multiply parentheses

8x-(-4(3x-2)+1)-20+8=0



We calculate terms in parentheses: -(-4(3x-2)+1), so:

-4(3x-2)+1

We multiply parentheses

-12x+8+1

We add all the numbers together, and all the variables

-12x+9

Back to the equation:

-(-12x+9)



We add all the numbers together, and all the variables

8x-(-12x+9)-12=0

We get rid of parentheses

8x+12x-9-12=0

We add all the numbers together, and all the variables

20x-21=0

We move all terms containing x to the left, all other terms to the right

20x=21

x=21/20

x=1+1/20

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