8+4(4x-4)=8-5(2x+1)

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Solution for 8+4(4x-4)=8-5(2x+1) equation: 



8+4(4x-4)=8-5(2x+1)

We move all terms to the left:

8+4(4x-4)-(8-5(2x+1))=0

We multiply parentheses

16x-(8-5(2x+1))-16+8=0



We calculate terms in parentheses: -(8-5(2x+1)), so:

8-5(2x+1)

determiningTheFunctionDomain
-5(2x+1)+8

We multiply parentheses

-10x-5+8

We add all the numbers together, and all the variables

-10x+3

Back to the equation:

-(-10x+3)



We add all the numbers together, and all the variables

16x-(-10x+3)-8=0

We get rid of parentheses

16x+10x-3-8=0

We add all the numbers together, and all the variables

26x-11=0

We move all terms containing x to the left, all other terms to the right

26x=11

x=11/26

x=11/26

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