8+4(5y-6)=-2(2y-1)+8y

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Solution for 8+4(5y-6)=-2(2y-1)+8y equation: 



8+4(5y-6)=-2(2y-1)+8y

We move all terms to the left:

8+4(5y-6)-(-2(2y-1)+8y)=0

We multiply parentheses

20y-(-2(2y-1)+8y)-24+8=0



We calculate terms in parentheses: -(-2(2y-1)+8y), so:

-2(2y-1)+8y

We add all the numbers together, and all the variables

8y-2(2y-1)

We multiply parentheses

8y-4y+2

We add all the numbers together, and all the variables

4y+2

Back to the equation:

-(4y+2)



We add all the numbers together, and all the variables

20y-(4y+2)-16=0

We get rid of parentheses

20y-4y-2-16=0

We add all the numbers together, and all the variables

16y-18=0

We move all terms containing y to the left, all other terms to the right

16y=18

y=18/16

y=1+1/8

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