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8+4(x-5)=(2+4x)-5
We move all terms to the left:
8+4(x-5)-((2+4x)-5)=0
We add all the numbers together, and all the variables
4(x-5)-((4x+2)-5)+8=0
We multiply parentheses
4x-((4x+2)-5)-20+8=0
We calculate terms in parentheses: -((4x+2)-5), so:We add all the numbers together, and all the variables
(4x+2)-5
We get rid of parentheses
4x+2-5
We add all the numbers together, and all the variables
4x-3
Back to the equation:
-(4x-3)
4x-(4x-3)-12=0
We get rid of parentheses
4x-4x+3-12=0
We add all the numbers together, and all the variables
-9!=0
There is no solution for this equation
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