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8+4a=6(1a/2)+5
We move all terms to the left:
8+4a-(6(1a/2)+5)=0
We add all the numbers together, and all the variables
4a-(6(+1a/2)+5)+8=0
We multiply all the terms by the denominator
4a*2)+5)-(6(+1a+8*2)+5)=0
We add all the numbers together, and all the variables
4a*2)+5)-(6(a+16)+5)=0
We add all the numbers together, and all the variables
4a*2)+5)-(6(a=0
Wy multiply elements
8a^2=0
a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$a=\frac{-b}{2a}=\frac{0}{16}=0$
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