8+5(2x-7)=3(x+2)-5

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Solution for 8+5(2x-7)=3(x+2)-5 equation: 



8+5(2x-7)=3(x+2)-5

We move all terms to the left:

8+5(2x-7)-(3(x+2)-5)=0

We multiply parentheses

10x-(3(x+2)-5)-35+8=0



We calculate terms in parentheses: -(3(x+2)-5), so:

3(x+2)-5

We multiply parentheses

3x+6-5

We add all the numbers together, and all the variables

3x+1

Back to the equation:

-(3x+1)



We add all the numbers together, and all the variables

10x-(3x+1)-27=0

We get rid of parentheses

10x-3x-1-27=0

We add all the numbers together, and all the variables

7x-28=0

We move all terms containing x to the left, all other terms to the right

7x=28

x=28/7

x=4

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