8+5(2y-2)=-2(3y-3)+4y

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Solution for 8+5(2y-2)=-2(3y-3)+4y equation: 



8+5(2y-2)=-2(3y-3)+4y

We move all terms to the left:

8+5(2y-2)-(-2(3y-3)+4y)=0

We multiply parentheses

10y-(-2(3y-3)+4y)-10+8=0



We calculate terms in parentheses: -(-2(3y-3)+4y), so:

-2(3y-3)+4y

We add all the numbers together, and all the variables

4y-2(3y-3)

We multiply parentheses

4y-6y+6

We add all the numbers together, and all the variables

-2y+6

Back to the equation:

-(-2y+6)



We add all the numbers together, and all the variables

10y-(-2y+6)-2=0

We get rid of parentheses

10y+2y-6-2=0

We add all the numbers together, and all the variables

12y-8=0

We move all terms containing y to the left, all other terms to the right

12y=8

y=8/12

y=2/3

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