8+7/10h=6+1/5h

Solution for 8+7/10h=6+1/5h equation:

8+7/10h=6+1/5h

We move all terms to the left:

8+7/10h-(6+1/5h)=0


Domain of the equation: 10h!=0

h!=0/10

h!=0

h∈R



Domain of the equation: 5h)!=0

h!=0/1

h!=0

h∈R


We add all the numbers together, and all the variables

7/10h-(1/5h+6)+8=0

We get rid of parentheses

7/10h-1/5h-6+8=0

We calculate fractions


35h/50h^2+(-10h)/50h^2-6+8=0

We add all the numbers together, and all the variables

35h/50h^2+(-10h)/50h^2+2=0

We multiply all the terms by the denominator


35h+(-10h)+2*50h^2=0

Wy multiply elements

100h^2+35h+(-10h)=0

We get rid of parentheses

100h^2+35h-10h=0

We add all the numbers together, and all the variables

100h^2+25h=0

a = 100; b = 25; c = 0;
Δ = b2-4ac
Δ = 252-4·100·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25}{2*100}=\frac{-50}{200}
=-1/4
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25}{2*100}=\frac{0}{200}
=0
$