8+8(b-8)=7(2b-2)

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Solution for 8+8(b-8)=7(2b-2) equation: 



8+8(b-8)=7(2b-2)

We move all terms to the left:

8+8(b-8)-(7(2b-2))=0

We multiply parentheses

8b-(7(2b-2))-64+8=0



We calculate terms in parentheses: -(7(2b-2)), so:

7(2b-2)

We multiply parentheses

14b-14

Back to the equation:

-(14b-14)



We add all the numbers together, and all the variables

8b-(14b-14)-56=0

We get rid of parentheses

8b-14b+14-56=0

We add all the numbers together, and all the variables

-6b-42=0

We move all terms containing b to the left, all other terms to the right

-6b=42

b=42/-6

b=-7

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