8+r=3(2r+2)-3

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Solution for 8+r=3(2r+2)-3 equation: 



8+r=3(2r+2)-3

We move all terms to the left:

8+r-(3(2r+2)-3)=0



We calculate terms in parentheses: -(3(2r+2)-3), so:

3(2r+2)-3

We multiply parentheses

6r+6-3

We add all the numbers together, and all the variables

6r+3

Back to the equation:

-(6r+3)



We get rid of parentheses

r-6r-3+8=0

We add all the numbers together, and all the variables

-5r+5=0

We move all terms containing r to the left, all other terms to the right

-5r=-5

r=-5/-5

r=1

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