8+x2=8x+x-5

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Solution for 8+x2=8x+x-5 equation:



8+x2=8x+x-5
We move all terms to the left:
8+x2-(8x+x-5)=0
We add all the numbers together, and all the variables
x2-(9x-5)+8=0
We add all the numbers together, and all the variables
x^2-(9x-5)+8=0
We get rid of parentheses
x^2-9x+5+8=0
We add all the numbers together, and all the variables
x^2-9x+13=0
a = 1; b = -9; c = +13;
Δ = b2-4ac
Δ = -92-4·1·13
Δ = 29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{29}}{2*1}=\frac{9-\sqrt{29}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{29}}{2*1}=\frac{9+\sqrt{29}}{2} $

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