8-(-2b-11)=10(4-8b)

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Solution for 8-(-2b-11)=10(4-8b) equation: 



8-(-2b-11)=10(4-8b)

We move all terms to the left:

8-(-2b-11)-(10(4-8b))=0

We add all the numbers together, and all the variables

-(-2b-11)-(10(-8b+4))+8=0

We get rid of parentheses

2b-(10(-8b+4))+11+8=0



We calculate terms in parentheses: -(10(-8b+4)), so:

10(-8b+4)

We multiply parentheses

-80b+40

Back to the equation:

-(-80b+40)



We add all the numbers together, and all the variables

2b-(-80b+40)+19=0

We get rid of parentheses

2b+80b-40+19=0

We add all the numbers together, and all the variables

82b-21=0

We move all terms containing b to the left, all other terms to the right

82b=21

b=21/82

b=21/82

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