8-(2x+1)=40

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Solution for 8-(2x+1)=40 equation: 



8-(2x+1)=40

We move all terms to the left:

8-(2x+1)-(40)=0

We add all the numbers together, and all the variables

-(2x+1)-32=0

We get rid of parentheses

-2x-1-32=0

We add all the numbers together, and all the variables

-2x-33=0

We move all terms containing x to the left, all other terms to the right

-2x=33

x=33/-2

x=-16+1/2

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