8-(3+b)b=-9

Solution for 8-(3+b)b=-9 equation:

8-(3+b)b=-9

We move all terms to the left:

8-(3+b)b-(-9)=0

We add all the numbers together, and all the variables

-(b+3)b+8-(-9)=0

We add all the numbers together, and all the variables

-(b+3)b+17=0

We multiply parentheses

-b^2-3b+17=0

We add all the numbers together, and all the variables

-1b^2-3b+17=0

a = -1; b = -3; c = +17;
Δ = b2-4ac
Δ = -32-4·(-1)·17
Δ = 77
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{77}}{2*-1}=\frac{3-\sqrt{77}}{-2}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{77}}{2*-1}=\frac{3+\sqrt{77}}{-2}
$