8-(3-2x)=1+2(x+2)

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Solution for 8-(3-2x)=1+2(x+2) equation: 



8-(3-2x)=1+2(x+2)

We move all terms to the left:

8-(3-2x)-(1+2(x+2))=0

We add all the numbers together, and all the variables

-(-2x+3)-(1+2(x+2))+8=0

We get rid of parentheses

2x-(1+2(x+2))-3+8=0



We calculate terms in parentheses: -(1+2(x+2)), so:

1+2(x+2)

determiningTheFunctionDomain
2(x+2)+1

We multiply parentheses

2x+4+1

We add all the numbers together, and all the variables

2x+5

Back to the equation:

-(2x+5)



We add all the numbers together, and all the variables

2x-(2x+5)+5=0

We get rid of parentheses

2x-2x-5+5=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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