8-(3-x)=6+(3x+1)

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Solution for 8-(3-x)=6+(3x+1) equation: 



8-(3-x)=6+(3x+1)

We move all terms to the left:

8-(3-x)-(6+(3x+1))=0

We add all the numbers together, and all the variables

-(-1x+3)-(6+(3x+1))+8=0

We get rid of parentheses

1x-(6+(3x+1))-3+8=0



We calculate terms in parentheses: -(6+(3x+1)), so:

6+(3x+1)

determiningTheFunctionDomain
(3x+1)+6

We get rid of parentheses

3x+1+6

We add all the numbers together, and all the variables

3x+7

Back to the equation:

-(3x+7)



We add all the numbers together, and all the variables

x-(3x+7)+5=0

We get rid of parentheses

x-3x-7+5=0

We add all the numbers together, and all the variables

-2x-2=0

We move all terms containing x to the left, all other terms to the right

-2x=2

x=2/-2

x=-1

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