8-(3b+5)=-5+2(b-1)

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Solution for 8-(3b+5)=-5+2(b-1) equation:



8-(3b+5)=-5+2(b-1)
We move all terms to the left:
8-(3b+5)-(-5+2(b-1))=0
We get rid of parentheses
-3b-(-5+2(b-1))-5+8=0
We calculate terms in parentheses: -(-5+2(b-1)), so:
-5+2(b-1)
determiningTheFunctionDomain 2(b-1)-5
We multiply parentheses
2b-2-5
We add all the numbers together, and all the variables
2b-7
Back to the equation:
-(2b-7)
We add all the numbers together, and all the variables
-3b-(2b-7)+3=0
We get rid of parentheses
-3b-2b+7+3=0
We add all the numbers together, and all the variables
-5b+10=0
We move all terms containing b to the left, all other terms to the right
-5b=-10
b=-10/-5
b=+2

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