8-(3b-5)=-5+2(b+1)

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Solution for 8-(3b-5)=-5+2(b+1) equation: 



8-(3b-5)=-5+2(b+1)

We move all terms to the left:

8-(3b-5)-(-5+2(b+1))=0

We get rid of parentheses

-3b-(-5+2(b+1))+5+8=0



We calculate terms in parentheses: -(-5+2(b+1)), so:

-5+2(b+1)

determiningTheFunctionDomain
2(b+1)-5

We multiply parentheses

2b+2-5

We add all the numbers together, and all the variables

2b-3

Back to the equation:

-(2b-3)



We add all the numbers together, and all the variables

-3b-(2b-3)+13=0

We get rid of parentheses

-3b-2b+3+13=0

We add all the numbers together, and all the variables

-5b+16=0

We move all terms containing b to the left, all other terms to the right

-5b=-16

b=-16/-5

b=3+1/5

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