8-(3k-2)=-5(k-3)-(4k-3)

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Solution for 8-(3k-2)=-5(k-3)-(4k-3) equation: 



8-(3k-2)=-5(k-3)-(4k-3)

We move all terms to the left:

8-(3k-2)-(-5(k-3)-(4k-3))=0

We get rid of parentheses

-3k-(-5(k-3)-(4k-3))+2+8=0



We calculate terms in parentheses: -(-5(k-3)-(4k-3)), so:

-5(k-3)-(4k-3)

We multiply parentheses

-5k-(4k-3)+15

We get rid of parentheses

-5k-4k+3+15

We add all the numbers together, and all the variables

-9k+18

Back to the equation:

-(-9k+18)



We add all the numbers together, and all the variables

-3k-(-9k+18)+10=0

We get rid of parentheses

-3k+9k-18+10=0

We add all the numbers together, and all the variables

6k-8=0

We move all terms containing k to the left, all other terms to the right

6k=8

k=8/6

k=1+1/3

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