8-(3w-2)=(-5)(w-3)-(4w-3)

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Solution for 8-(3w-2)=(-5)(w-3)-(4w-3) equation: 



8-(3w-2)=(-5)(w-3)-(4w-3)

We move all terms to the left:

8-(3w-2)-((-5)(w-3)-(4w-3))=0

We get rid of parentheses

-3w-((-5)(w-3)-(4w-3))+2+8=0

We multiply parentheses ..

-3w-((-5w+15)-(4w-3))+2+8=0



We calculate terms in parentheses: -((-5w+15)-(4w-3)), so:

(-5w+15)-(4w-3)

We get rid of parentheses

-5w-4w+15+3

We add all the numbers together, and all the variables

-9w+18

Back to the equation:

-(-9w+18)



We add all the numbers together, and all the variables

-3w-(-9w+18)+10=0

We get rid of parentheses

-3w+9w-18+10=0

We add all the numbers together, and all the variables

6w-8=0

We move all terms containing w to the left, all other terms to the right

6w=8

w=8/6

w=1+1/3

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