8-(3x-4)=-4(2x+5)

Solution for 8-(3x-4)=-4(2x+5) equation:

8-(3x-4)=-4(2x+5)

We move all terms to the left:

8-(3x-4)-(-4(2x+5))=0

We get rid of parentheses

-3x-(-4(2x+5))+4+8=0


We calculate terms in parentheses: -(-4(2x+5)), so:

-4(2x+5)

We multiply parentheses

-8x-20

Back to the equation:

-(-8x-20)


We add all the numbers together, and all the variables

-3x-(-8x-20)+12=0

We get rid of parentheses

-3x+8x+20+12=0

We add all the numbers together, and all the variables

5x+32=0

We move all terms containing x to the left, all other terms to the right

5x=-32

x=-32/5

x=-6+2/5