8-(3y+2)=-3(1-3y)

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Solution for 8-(3y+2)=-3(1-3y) equation: 



8-(3y+2)=-3(1-3y)

We move all terms to the left:

8-(3y+2)-(-3(1-3y))=0

We add all the numbers together, and all the variables

-(3y+2)-(-3(-3y+1))+8=0

We get rid of parentheses

-3y-(-3(-3y+1))-2+8=0



We calculate terms in parentheses: -(-3(-3y+1)), so:

-3(-3y+1)

We multiply parentheses

9y-3

Back to the equation:

-(9y-3)



We add all the numbers together, and all the variables

-3y-(9y-3)+6=0

We get rid of parentheses

-3y-9y+3+6=0

We add all the numbers together, and all the variables

-12y+9=0

We move all terms containing y to the left, all other terms to the right

-12y=-9

y=-9/-12

y=3/4

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