8-(4c+3)2=6-(4-8c)

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Solution for 8-(4c+3)2=6-(4-8c) equation: 



8-(4c+3)2=6-(4-8c)

We move all terms to the left:

8-(4c+3)2-(6-(4-8c))=0

We add all the numbers together, and all the variables

-(4c+3)2-(6-(-8c+4))+8=0

We multiply parentheses

-8c-(6-(-8c+4))-6+8=0



We calculate terms in parentheses: -(6-(-8c+4)), so:

6-(-8c+4)

determiningTheFunctionDomain
-(-8c+4)+6

We get rid of parentheses

8c-4+6

We add all the numbers together, and all the variables

8c+2

Back to the equation:

-(8c+2)



We add all the numbers together, and all the variables

-8c-(8c+2)+2=0

We get rid of parentheses

-8c-8c-2+2=0

We add all the numbers together, and all the variables

-16c=0

c=0/-16

c=0

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