8-(4z+4)=6z-4

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Solution for 8-(4z+4)=6z-4 equation: 



8-(4z+4)=6z-4

We move all terms to the left:

8-(4z+4)-(6z-4)=0

We get rid of parentheses

-4z-6z-4+4+8=0

We add all the numbers together, and all the variables

-10z+8=0

We move all terms containing z to the left, all other terms to the right

-10z=-8

z=-8/-10

z=4/5

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