8-(6x-8)=-7(x+1)-5

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Solution for 8-(6x-8)=-7(x+1)-5 equation: 



8-(6x-8)=-7(x+1)-5

We move all terms to the left:

8-(6x-8)-(-7(x+1)-5)=0

We get rid of parentheses

-6x-(-7(x+1)-5)+8+8=0



We calculate terms in parentheses: -(-7(x+1)-5), so:

-7(x+1)-5

We multiply parentheses

-7x-7-5

We add all the numbers together, and all the variables

-7x-12

Back to the equation:

-(-7x-12)



We add all the numbers together, and all the variables

-6x-(-7x-12)+16=0

We get rid of parentheses

-6x+7x+12+16=0

We add all the numbers together, and all the variables

x+28=0

We move all terms containing x to the left, all other terms to the right

x=-28

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