8-(b-2=1)

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Solution for 8-(b-2=1) equation: 



8-(b-2=1)

We move all terms to the left:

8-(b-2-(1))=0

We add all the numbers together, and all the variables

-(b-3)+8=0

We get rid of parentheses

-b+3+8=0

We add all the numbers together, and all the variables

-1b+11=0

We move all terms containing b to the left, all other terms to the right

-b=-11

b=-11/-1

b=+11

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