8-(x-2)=2x+(10-3x)

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Solution for 8-(x-2)=2x+(10-3x) equation: 



8-(x-2)=2x+(10-3x)

We move all terms to the left:

8-(x-2)-(2x+(10-3x))=0

We add all the numbers together, and all the variables

-(x-2)-(2x+(-3x+10))+8=0

We get rid of parentheses

-x-(2x+(-3x+10))+2+8=0



We calculate terms in parentheses: -(2x+(-3x+10)), so:

2x+(-3x+10)

We get rid of parentheses

2x-3x+10

We add all the numbers together, and all the variables

-1x+10

Back to the equation:

-(-1x+10)



We add all the numbers together, and all the variables

-1x-(-1x+10)+10=0

We get rid of parentheses

-1x+1x-10+10=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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