8-(x-4)=-2(x-6)+x

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Solution for 8-(x-4)=-2(x-6)+x equation: 



8-(x-4)=-2(x-6)+x

We move all terms to the left:

8-(x-4)-(-2(x-6)+x)=0

We get rid of parentheses

-x-(-2(x-6)+x)+4+8=0



We calculate terms in parentheses: -(-2(x-6)+x), so:

-2(x-6)+x

We add all the numbers together, and all the variables

x-2(x-6)

We multiply parentheses

x-2x+12

We add all the numbers together, and all the variables

-1x+12

Back to the equation:

-(-1x+12)



We add all the numbers together, and all the variables

-1x-(-1x+12)+12=0

We get rid of parentheses

-1x+1x-12+12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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