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8-1/2(2x-10)=x+1+2x
We move all terms to the left:
8-1/2(2x-10)-(x+1+2x)=0
Domain of the equation: 2(2x-10)!=0We add all the numbers together, and all the variables
x∈R
-1/2(2x-10)-(3x+1)+8=0
We get rid of parentheses
-1/2(2x-10)-3x-1+8=0
We multiply all the terms by the denominator
-3x*2(2x-10)-1*2(2x-10)+8*2(2x-10)-1=0
Wy multiply elements
-6x^2(2-2x(2+16x(2-1=0
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