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8-1/2y=1/4y-7
We move all terms to the left:
8-1/2y-(1/4y-7)=0
Domain of the equation: 2y!=0
y!=0/2
y!=0
y∈R
Domain of the equation: 4y-7)!=0We get rid of parentheses
y∈R
-1/2y-1/4y+7+8=0
We calculate fractions
(-4y)/8y^2+(-2y)/8y^2+7+8=0
We add all the numbers together, and all the variables
(-4y)/8y^2+(-2y)/8y^2+15=0
We multiply all the terms by the denominator
(-4y)+(-2y)+15*8y^2=0
Wy multiply elements
120y^2+(-4y)+(-2y)=0
We get rid of parentheses
120y^2-4y-2y=0
We add all the numbers together, and all the variables
120y^2-6y=0
a = 120; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·120·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*120}=\frac{0}{240} =0 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*120}=\frac{12}{240} =1/20 $
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