8-12x=6(1-x)

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Solution for 8-12x=6(1-x) equation: 



8-12x=6(1-x)

We move all terms to the left:

8-12x-(6(1-x))=0

We add all the numbers together, and all the variables

-12x-(6(-1x+1))+8=0



We calculate terms in parentheses: -(6(-1x+1)), so:

6(-1x+1)

We multiply parentheses

-6x+6

Back to the equation:

-(-6x+6)



We get rid of parentheses

-12x+6x-6+8=0

We add all the numbers together, and all the variables

-6x+2=0

We move all terms containing x to the left, all other terms to the right

-6x=-2

x=-2/-6

x=1/3

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